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Answer» Given : Median = 32.5 , which belongs to the CLASS 30 - 40 . So the Median class is 30 - 40 Given : n(Σfi) = 40 Here, n = 40n/2 = 20From the table , l = 30, f = 12, cf = (14 + f1) , H = 10MEDIAN = l + [(n/2 - cf )/f ] ×h32.5 = 30 +[ 20- (14+f1)/12] ×1032.5 - 30 = [(20- 14 + f1)/12] ×102.5 =[ (6 - f1)/12 ]×102.5 × 12 = 60 -10 f130 - 60= -10f1-30 = -10f1f1 = 30/10 = 3 f1 = 3 Given : Σfi = 40 31 + f1 + f2 = 40 [from the table]f1 + f2 = 40 - 313 + f2 = 9 [f1 = 3]f2 = 9 - 3f2 = 6 Hence, the missing frequencies be f1 = 3 and f2 = 6★★ MEDIAN = l + [(n/2 - cf )/f ] ×hWhere,l = lower LIMIT of the median classn = number of observations cf = cumulative frequency of class interval preceding the median classf = frequency of median classh = class sizeHOPE THIS ANSWER WILL HELP YOU…Explanation:i help you by giving answer so you help me by making me brainlist |
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