Saved Bookmarks
| 1. |
Please solve this question! Please solve this question fast |
Answer» ExplanationThe standard equation of transverse wave is y = asin[2πt / T - 2πx/λ ] Given equation is y = 4sin π/6 sin ( 15t - 3X ) COMPARING EQ [i] and with Eq [i] 2π/λ = 3 ∴ λv= 2π/3 and 2π/T = 15 T = 2π/15 ∴ SPEED of PROPAGATION wave, v = λ/T = 2π/3/(2π/15) = 5 ! |
|