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Explanation

The standard equation of transverse wave is

y = asin[2πt / T - 2πx/λ ]

Given equation is

y = 4sin π/6 sin ( 15t - 3X )

COMPARING EQ [i] and with Eq [i]

2π/λ = 3

∴ λv= 2π/3 and 2π/T = 15

T = 2π/15

SPEED of PROPAGATION wave, v = λ/T = 2π/3/(2π/15) = 5 !



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