Position of a particle moving along x-axis is givenby x 2 8t - 4t2. Th

1.	Position of a particle moving along x-axis is givenby x 2 8t - 4t2. The distance travelled by theparticle trom t-O to t-2 is:(2) 8(3) 12(4) 16
Answer» the answer is 8 v= dx/dt= 8-8t at t=1 you get v=0 and the particle stops and reverses direction split the integral of v into two region 0<=t<=1 and 1<t<=2 and later add them together and get the solution x1= 8t-4t^2 81-4*1^2= 4 m x2 = [0-(8-4)] = 4 m x=x1+x2 = 8 m why we did integration of v

Position of a particle moving along x-axis is givenby x 2 8t - 4t2. The distance travelled by theparticle trom t-O to t-2 is:(2) 8(3) 12(4) 16

Answer»

the answer is 8

v= dx/dt= 8-8*t at t=1 you get v=0 and the particle stops and reverses direction split the integral of v into two region 0<=t<=1 and 1<t<=2 and later add them together and get the solution

x1= 8*t-4*t^2 8*1-4*1^2= 4 m x2 = [0-(8-4)] = 4 m x=x1+x2 = 8 m

why we did integration of v

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Position of a particle moving along x-axis is givenby x 2 8t - 4t2. The distance travelled by theparticle trom t-O to t-2 is:(2) 8(3) 12(4) 16

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