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Position vector of a moving particle is given by r = [(î -j )t (1-5)] m. Calculate the velocity of the particle at t=1s.​

Answer»

Explanation:15m/s CORRECT answer is A. a=2(t−1) =2t−2 DT dv ​ =2t−2 dv=(2t−2)dt INTEGRATING both side we get, ∫dv=∫(2t−2)dt v=t  2 −2t+c =(5)  2 −2×5 =25−10 =15m/s



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