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Pre-Medical40. Starting from rest ,the acceleration of a particle is、a 2ft-1). The velocity of the particle at t- 5 sis:(1) 15 m/s(2) 25 m/s(4) of these(3) 5 m/sons renresents the

Answer»

As we know that change in velocity divided by change in time is the acceleration, we can write

dv/dt = adv = a dt

Now integrate both the sides. Limit the velocity from 0 to v.

Limit the time from 0 to 5.dv = 2 (t-1) dt

After integration:V = t^2 - 2t.

Now using the limits,

v = 5^2 - 2 (5)V = 25 - 10 = 15.

Hence the answer is 15m/s.



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