1.

PROBLEM 01 - 0003: The bar is a unit ofpressure defined as 1.00 x 10dynes/cm, or 1.00 x105 N/m2. What is theequivalent of thebar in units of mmHg?9

Answer»

The gallium column can be computed by the use of the defini­tion:(hGa) (dGa) = (hHg) (dHg)whereh = height of a column,d = density,therefore hGa = [{(hHg) (dHg)} / (dGa)]1 atm pressure = hHg = 760 mm Hg = 76.0 cm Hg. The density ofmercury = dHg = 13.6 gm/cm3 . Therefore, hGa = [{(76.0 cm Hg) (13.6 gm/cm3)} / (6.09 gm/cm3)] = 169.7 cm Ga = 1697 mm Ga



Discussion

No Comment Found

Related InterviewSolutions