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Prove : ` nPr = n (n-1)P(r-1)` |
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Answer» `.^nP_r=.^nC_r*r!` `=(n!)/((n-r)!*r!)*r!` `=(n!)/(n-r)!`. `=n (n-1)!*(r-1)!` `=n*(n-1)C_(r-1)*(r-1)!` `n*(n-1)P_(r-1)` |
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