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Prove:sinθ sin (90° – θ) – cos θ cos (90° – θ) = 0 |
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Answer» Taking the L.H.S, sinθ sin (90° – θ) – cos θ cos (90° – θ) = sin θ cos θ – cos θ sin θ [∵ sin (90 – θ) = cos θ and cos (90 – θ) = sin θ] = 0 |
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