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Prove that :cos 27° + sin51° = sin63° + cos 39°

Answer»

Taking LHS = cos 27° + sin51o

We know that

cos θ = sin (90° - θ)

Here, θ = 27°

⇒ sin (90° - 27°)+ sin 51°

⇒ sin 63°+ sin 51°

We also know that

Sin θ = cos (90° - θ)

Here, θ = 51°

⇒ sin 63°+ cos (90° - 51°)

⇒ sin 63°+ cos 39° = RHS

Hence Proved



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