1.

Prove that :cos θ . cos(90° – θ) + sin θ sin (90° – θ) = 0

Answer»

Taking LHS = cos θ cos ( 90° - θ) + sin θ sin (90° - θ)

⇒ cos θ × sin θ – sinθ × cos θ [∵ Sin θ = cos (90° - θ) and cos θ = sin (90° - θ) ]

= 0 = RHS

Hence Proved



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