1.

Prove that (cos2θ/sinθ)-cosecθ+sinθ=0Prove that (cos2 theta/sin theta)-cosec theta+sin theta=0

Answer»

LHS= (cos2θ-sinθcosecθ+sin2θ)/sinθ

= (cos2θ+sin2θ-1)/sinθ  [Therefore sinθcosecθ=1]

=0

=LHS =RHS Hence proved



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