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Prove that (cos2θ/sinθ)-cosecθ+sinθ=0Prove that (cos2 theta/sin theta)-cosec theta+sin theta=0 |
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Answer» LHS= (cos2θ-sinθcosecθ+sin2θ)/sinθ = (cos2θ+sin2θ-1)/sinθ [Therefore sinθcosecθ=1] =0 =LHS =RHS Hence proved |
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