1.

Prove that cosec2 72° − tan2 18° = 1

Answer»

cosec2 72° − tan2 18° = 1

LHS = cosec2 72° – tan2 18°

= cosec2 72° – tan2 (90 – 72)°

= cosec2 72° – cot2 72°

= 1 = RHS



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