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Prove that \(\frac{cos2A}{secA}\) + \(\frac{sin2A}{cosA}\) = cosA |
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Answer» L.H.S. = cos2A .\(\frac{1}{secA}\) + sin 2A .\(\frac{1}{cosA}\) = cos2A . cosA + sin2A . sinA = cos(2A – A) = cosA = R.H.S. |
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