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Prove that: (sin θ – cosec θ)2 + (cos θ – sec θ)2 = cot2 θ + tan2 θ – 1 |
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Answer» (sin θ – cosec θ)2 + (cos θ – sec θ)2 = sin2 θ + cosec2 θ – 2 sinθ . cosecθ . + cos2 θ + sec2 θ – 2 cosθ . sec θ = (sin2 θ + cos2 θ) + cosec2 θ + sec2 θ – 2 – 2 = 1 + (1 + cot2 θ) + (1 + tan2 θ) – 2 – 2 = cot2 θ + tan2 θ + 3 – 4 = cot2 θ + tan2 θ – 1 |
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