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Prove that tan2 A – sin2 A = tan2 A . sin2 A. |
Answer» tan2 A – sin2 A = \(\frac{sin^2\,A}{cos^2\,A}\) – sin2 A sin2 A ( \(\frac{1}{cos^2\,A}\) – 1 ) = sin2 A (sec2 A – 1) = sin2 A. tan2 A |
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