InterviewSolution
Saved Bookmarks
| 1. |
Prove that the curves x=4 `(costheta+sintheta)` and y=3 `(costheta-sintheta)` represents an ellipse. |
|
Answer» `x=4(costheta+sintheta)` `rArr" "(x)/(4)=costheta+sintheta` . . . (1) and `y=3(costheta+sintheta)` `rArr" "(y)/(3)=costheta-sintheta` . . . (2) Squaring and adding eqs. (1) and (2) `(x^(2))/(16)+(y^(2))/(9)=(costheta+sintheta)^(2)+(costheta-sintheta)^(2)=2` `rArr" "9x^(2)+16y^(2)=288`. |
|