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Prove that the points (-2, 5), (0, 1) and (2, -3) are collinear. |
Answer» Let A (-2, 5), B(0, 1) and C (2, -3) be the given points So, we have AB = √[(0 – (-2))2 + (1 – 5)2] = √[(2)2 + (-4)2] = √[4 + 16] = √20 = 2√5 units BC = √[(2 – 0)2 + (-3 – 1)2] = √[(2)2 + (-4)2] = √[4 + 16] = √20 = 2√5 units AC = √[(2 – (-2))2 + (-3 – 5)2] = √[(4)2 + (-8)2] = √[16 + 64] = √80 = 4√5 units Now, it’s seen that AB + BC = AC 2√5 + 2√5 = 4√5 4√5 = 4√5 Therefore, we can conclude that the given points (-2, 5), (0, 1) and (2, -3) are collinear. |
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