1.

Prove that the points (-2, 5), (0, 1) and (2, -3) are collinear.

Answer»

Let A (-2, 5), B(0, 1) and C (2, -3) be the given points

So, we have

AB = √[(0 – (-2))2 + (1 – 5)2

= √[(2)2 + (-4)2

= √[4 + 16] 

= √20 

= 2√5 units

BC = √[(2 – 0)2 + (-3 – 1)2

= √[(2)2 + (-4)2

= √[4 + 16] 

= √20 

= 2√5 units

AC = √[(2 – (-2))2 + (-3 – 5)2

= √[(4)2 + (-8)2

= √[16 + 64] 

= √80 

= 4√5 units

Now, it’s seen that

AB + BC = AC

2√5 + 2√5 = 4√5

4√5 = 4√5

Therefore, we can conclude that the given points (-2, 5), (0, 1) and (2, -3) are collinear.



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