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Prove that the tangents to the curve `y=x^2-5+6`at the points `(2,0)a n d(3,0)`are at right angles. |
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Answer» `y= x^2 - 5x + 6` at point `(2,0)` `dy/dx = 2x- 5` at (2,0) , `dy/dx = -1` at (3,0)`dy/dx= 1` `(m_1)(m_2) = -1` so, they are at right angles hence proved |
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