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Prove that `(veca-vecb)xx(veca+vecb)=2(vecaxxvecb)` also interpret this result. |
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Answer» `(veca-vecb)xx(veca+vecb)=(veca-vecb) xxveca+(veca-vecb)xxvecb` [ By distributivity of vector product over addition] `= vecaxxveca-vecbexxveca+vecaxxvecb-vecbxxvecb` [ Again , by distributivity of vector product over addition ] `=vec0 +vecaxxvecb+vecaxxvecb-vec0` `= 2vecaxxvecb` |
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