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Prove that : `vecixx(vecaxxveci)+vecjx(vecaxxvecj)+veckxx(vecaxxveck)=vec(2a)`

Answer» `hatixx(veca xxhati)=(hati.hati)veca-(veca.veci)=veca-(veca.veci)hati`
`hatjxx(vecaxxhatj)=veca-(veca.hatj)and hatkxx(vecaxxhatk)veca-(veca.hatk)hatk`.
`hatixx(vecaxxhati)+hatjxx(vecaxxhatj)+hatkxx(vecaxxhatk)=3veca-((veca.hati)hati+(veca.hatj)+(vecaxx hatk)hatk)=2veca`


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