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Prove the following: cos θ + sin (270° + θ) – sin (270° – θ) + cos (180° + θ) = 0 |
Answer» L.H.S. = cos θ + sin (270° + θ) – sin (270° – θ) + cos (180° + θ) = cos θ + (- cos θ)-(- cos θ) – cos θ = cos θ – cos θ + cos θ – cos θ = 0 = R.H.S. |
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