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Prove the following identities :(sinθ + cosθ)2 + (sinθ – cosθ)2 = 2 |
Answer» Taking LHS = (sin θ + cos θ)2 + (sin θ – cos θ)2 Using the identity,(a + b)2 = (a2 + b2 + 2ab) and (a – b)2 = (a2 + b2 – 2ab) = sin2 θ + cos2 θ + 2sin θ cos θ + sin2 θ + cos2 θ – 2sin θ cos θ = 1 +1 [∵ cos2 θ + sin2 θ = 1] = 2 = RHS Hence Proved |
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