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Prove the followings identities:(1 + cos θ)(1 – cos θ) = sin2θ |
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Answer» Taking LHS = (1 – cosθ)(1+ cosθ) Using identity , (a + b) (a – b) = (a2 – b2) , we get = (1)2 – (cosθ)2 = 1 – cos2 θ = sin2 θ [∵ cos2 θ + sin2 θ = 1] = RHS Hence Proved |
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