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Q.19) A body starting from rest has anacceleration of 20ms Calculate,(a.) distance travelled by body in 8sec.b.) Velocity after travelling a distance10m.(c.) distance travelled by it in 5th second​

Answer»

ANSWER:

a) 640m

b)20m/s

c)250m

Explanation:

a)s=ut+1/2at^2

s=0×8+1/2×20×8×8

s=640m

b)v^2-u^2=2as

v^2-0^2=2as

v^2=2as

v^2=2×20×10

v=√400

v=20m/s

c)again

s=ut+1/2at^2

s=0×5+1/2×20×5×5

s=250m



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