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Q.19) A body starting from rest has anacceleration of 20ms Calculate,(a.) distance travelled by body in 8sec.b.) Velocity after travelling a distance10m.(c.) distance travelled by it in 5th second |
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Answer» a) 640m b)20m/s c)250m Explanation: a)s=ut+1/2at^2 s=0×8+1/2×20×8×8 s=640m b)v^2-u^2=2as v^2-0^2=2as v^2=2as v^2=2×20×10 v=√400 v=20m/s c)again s=ut+1/2at^2 s=0×5+1/2×20×5×5 s=250m |
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