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Q.1The position x of a particle varies with time (t) asx = at - bt. The acceleration at time t of theparticle will be equal to zero, where t is equal to-[AIPMT-1997)(2)(4) zero |
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Answer» Given, x = at^2 - bt^3 Then, Velocity = dx/dt= 2at - 3bt^2 Acceleration = d^2x/dt^2 = 2a - 6bt Now, Acceleration = 02a - 6bt = 0t = 2a/6b = a/3b (3) is correct option option 3 is correct answer option 3 is correct using calculas method |
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