Q. 4. Derive an expression for difference in tensions at highest and l

1.	Q. 4. Derive an expression for difference in tensions at highest and lowest point for a particle performing verticalcircular motion.
Answer» We consider a particle of mass m is performing vertical circular motion of a circle of radius r. at highest position, weight and tension in string both are along downward direction.now, at the highest position, T + mg = mv²/r .........(1) here, v = √(gh) it is velocity at uttermost position in case of string.so, T + mg = mg = 0 again, at lowermost position, weight and tension in string both are in opposite directions. tension acts radially inward while weight radially outward. now , at the lowermost position, T' - mg = mv'²/r ........(2)here, v = √(5gh), it is velocity at Lowest position in case of string.so, T' - mg = 5mgh , T' = 6mg now, difference in tension at lowest and uttermost point for a particle performing vertical circular motion = T' - T = 6mg.

Q. 4. Derive an expression for difference in tensions at highest and lowest point for a particle performing verticalcircular motion.

Answer»

We consider a particle of mass m is performing vertical circular motion of a circle of radius r.

at highest position, weight and tension in string both are along downward direction.now, at the highest position, T + mg = mv²/r .........(1) here, v = √(gh) it is velocity at uttermost position in case of string.so, T + mg = mg = 0

again, at lowermost position, weight and tension in string both are in opposite directions. tension acts radially inward while weight radially outward. now , at the lowermost position, T' - mg = mv'²/r ........(2)here, v = √(5gh), it is velocity at Lowest position in case of string.so, T' - mg = 5mgh , T' = 6mg now, difference in tension at lowest and uttermost point for a particle performing vertical circular motion = T' - T = 6mg.

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