Q.Two bulbs of ratings 20v-200w and 20v-50w are connected in series wi

1.	Q.Two bulbs of ratings 20v-200w and 20v-50w are connected in series with 40w power supply find total current and power consumed.
Answer» Correct OPTION is B 40W Resistance of 100Wbulb=200 2 /100=400ohms Resistance of 60Wbulb=200 2 /60=666.67ohms Resistance of 40Wbulb=200 2 /40=1000ohms Therefore, total resistance in series = (400+666.67+1000)=2066.67ohms Current in the CIRCUIT =200/2066.67=0.0967A Therefore, actual power consumed by “40W”bulb=0.0967 2 x1000=9.35W (much LESSER than any of the original) The 40W bulb will GROW the brightest as the current is constant in all three and it has the maximum resistance. But it would consume much LESS than 40W as the bulbs are connected in series, and voltage would be divided across all three filaments depending upon resistances.

Q.Two bulbs of ratings 20v-200w and 20v-50w are connected in series with 40w power supply find total current and power consumed.

Answer»

Correct OPTION is

40W

Resistance of 100Wbulb=200

/100=400ohms

Resistance of 60Wbulb=200

/60=666.67ohms

Resistance of 40Wbulb=200

/40=1000ohms

Therefore, total resistance in series = (400+666.67+1000)=2066.67ohms

Current in the CIRCUIT =200/2066.67=0.0967A

Therefore, actual power consumed by “40W”bulb=0.0967

x1000=9.35W (much LESSER than any of the original)

The 40W bulb will GROW the brightest as the current is constant in all three and it has the maximum resistance. But it would consume much LESS than 40W as the bulbs are connected in series, and voltage would be divided across all three filaments depending upon resistances.

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