Q.what is the amount of work done bya: the earth's gravitational force

1.	Q.what is the amount of work done bya: the earth's gravitational force in keeping the moon in its circular orbit around the earth?b: an electron moving with half the speed of light in empty space free of all forces and for from all matters?
Answer» 1. In this case work done is zero because force direction to the motion is perpendicular THUS W =FScos 90degree now W=FS0 (cos 90=0) thus W =0 2. since all force is zero so the work done by electron will be zero as we known that W =F*S F =0 then W= 0 hope this help you

Q.what is the amount of work done bya: the earth's gravitational force in keeping the moon in its circular orbit around the earth?b: an electron moving with half the speed of light in empty space free of all forces and for from all matters?

Answer»

1. In this case work done is zero because force direction to the motion is perpendicular

THUS W =F*S*cos 90degree

now W=F*S*0 (cos 90=0)

thus W =0

2. since all force is zero so the work done by electron will be zero

as we known that

W =F*S

F =0

then

W= 0

hope this help you

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Q.what is the amount of work done bya: the earth's gravitational force in keeping the moon in its circular orbit around the earth?b: an electron moving with half the speed of light in empty space free of all forces and for from all matters?​

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Q.what is the amount of work done bya: the earth's gravitational force in keeping the moon in its circular orbit around the earth?b: an electron moving with half the speed of light in empty space free of all forces and for from all matters?