Q1) A particle is projected with 200 m/sat an angle 60°. At the highe

1.	Q1) A particle is projected with 200 m/sat an angle 60°. At the highest point, itexplodes into three parts of equalmasses. One goes vertically upwardswith velocity 100 m/s, second particlegoes vertically downwards. Then thevelocity of the third particle will be..AFMC 1997]a)200 m/sb) 300 m/sc)120 m/s with 60° angled)200 m/s with 30 angle
Answer» At highest point velocity of particle is vcosθ=200 cos 60=100 m/sLet the mass of particle be 3mIt is given that two particles of equal mass and same magnitude of velocity goes opposite to each other one goes up while other goes down, thus they cancel each other momentum.refer figure below Now the last fraction of mass will have momentum equal to the momentum of particle before explosion∴ 3m(100)=m(v') according to law of conservation of energy∴ v'=300 m/s along x axis Answer: (b)

Q1) A particle is projected with 200 m/sat an angle 60°. At the highest point, itexplodes into three parts of equalmasses. One goes vertically upwardswith velocity 100 m/s, second particlegoes vertically downwards. Then thevelocity of the third particle will be..AFMC 1997]a)200 m/sb) 300 m/sc)120 m/s with 60° angled)200 m/s with 30 angle

Answer»

At highest point velocity of particle is vcosθ=200 cos 60=100 m/sLet the mass of particle be 3mIt is given that two particles of equal mass and same magnitude of velocity goes opposite to each other one goes up while other goes down, thus they cancel each other momentum.refer figure below

Now the last fraction of mass will have momentum equal to the momentum of particle before explosion∴ 3m(100)=m(v') according to law of conservation of energy∴ v'=300 m/s along x axis Answer: (b)

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