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Q6. P+Q+R 0 andP 3,Q 4 and R 5, anglebetween and R is tan374d d 420(2) 37°

Answer»

Given P+Q+R= 0. , |P| = 3, |Q| = 4 and |R| = 5let the angle between Q and R is ∅

now Q+R = -P on squaring both side (Q+R)² = P²

=> |Q|² + |R|² + 2.|Q||R|cos∅ = |P|² => 4²+5²+ 2*4*5cos∅ = 3²=> 40cos∅ = 9-16-25 = -32so, cos∅ = -32/40 = -4/5

so, tan∅ = 3/4 , 37°



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