InterviewSolution
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Quantity B: Probability of selection of a boy in an interview is 1/2 and that of a girl is 5/9. What is the probability that one of them will be selected?1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» Quantity A: 2 DIGITS NUMBERS less than 50 which are divisible by 2 or 3 or 5 but not by 6 and 15 = 10, 14, 16, 20, 21, 22, 25, 26, 27, 28, 32, 33, 34, 35, 38, 39, 40, 44, 46 ⇒ n(E) = 19 n(S) = Total number of 2 digits numbers less than 50 (10 to 49) ⇒ n(S) = 40 ⇒ P(E) = n(E)/n(S) = 19/40 Quantity B: Probability of SELECTION of a boy in a interview is 1/2 and that of a girl is 5/9. ⇒ P(B) = 1/2 and P(G) = 5/9 ⇒ P($(\bar B)$) = 1 – 1/2 = 1/2 and P($(\bar G)$) = 1 – 5/9 = 4/9 Probability that ONE of them will be selected = P(B) × P($(\bar G)$) + P($(\bar B)$) × P(G) ⇒ 1/2 × 4/9 + 1/2 × 5/9 ⇒ 4/18 + 5/18 = 1/2 ∴ Quantity A < Quantity B |
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