1.

Quantity B: Probability of selection of a boy in an interview is 1/2 and that of a girl is 5/9. What is the probability that one of them will be selected?1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B

Answer»

Quantity A:

2 DIGITS NUMBERS less than 50 which are divisible by 2 or 3 or 5 but not by 6 and 15

= 10, 14, 16, 20, 21, 22, 25, 26, 27, 28, 32, 33, 34, 35, 38, 39, 40, 44, 46

⇒ n(E) = 19

n(S) = Total number of 2 digits numbers less than 50 (10 to 49)

⇒ n(S) = 40

⇒ P(E) = n(E)/n(S) = 19/40

Quantity B:

Probability of SELECTION of a boy in a interview is 1/2 and that of a girl is 5/9.

⇒ P(B) = 1/2 and P(G) = 5/9

⇒ P($(\bar B)$) = 1 – 1/2 = 1/2 and P($(\bar G)$) = 1 – 5/9 = 4/9

Probability that ONE of them will be selected = P(B) × P($(\bar G)$) + P($(\bar B)$) × P(G)

⇒ 1/2 × 4/9 + 1/2 × 5/9

⇒ 4/18 + 5/18 = 1/2

∴ Quantity A < Quantity B


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