1.

Ques i find relansation time for free e in coppur isdensity of mobile e is 8.4 x 1028 Im The resistivity oflas is 1.1 No 8n mat room temprature

Answer»

1/resistivity = density × e^2 × relaxation time/mass

relaxation time = mass/resistivity × density × e^2

= 9.1× 10^-31/1.7× 10^-8 × 8.4× 10^28 × 2.56 × 10^-38

= 9.1× 10^-31/10^-18 × 36.55

= 10^-13 × 0.25

= 2.5 × 10^-14



Discussion

No Comment Found

Related InterviewSolutions