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Question No: 26in the circuit shown in diagram potential difference between points A and B is 16 V. The c212 resistance will beÂŽ 35A(C) 4.0ADZero

Answer»

Assume the values of current in the main branch as well as in the loop.

Write equations of KCL and KVL for the loop and the branch.

Let the current in the 2 ohm resistor bei1+i2

then using KVL equation in closed loop

9−i2−2(i1+i2)=0..............(1)

4i1+2(i1+i2)−3+4i1=16.........(2)

solving we geti1=1.5andi2=2

Thus current through 2 ohm resistor is 3.5 amp



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