InterviewSolution
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InterviewSolution
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Rahul went to an electronics shop to get his father's old radio set repaired. The radio mechanic required resistances of 1.5 Omega and 10 Omega to repair the radio set properly but he had only a large number of 3 Omega resistors. The radio mechanic made many attempts but could not get the right combinations of 3 Omega resistors to obtain 1.5 Omega and 10 Omega resistances. Rahul had studied combination of resistors in class X. Rahul thought for a while and then joined some 3 Omega resistors in two different ways to obtain the required resistances. (a) How did Rahul obtain 1.5 Omega resistance by joining a number of 3 Omega resistors ? (b) How many 3 Omega resistors were combined together to obtain 1.5 Omega resistance ? (c) How did Rahul obtain 10 Omega resistance by joining a number of 3 Omega resistors ? (d) How many 3 Omega resistors were combined together by Rahul to obtain 10 Omega resistance ? (e) What values are shown by Rahul in this apisode ? |
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Answer» Solution :(a) In ORDER to obtain `1.5 Omega` resistance, Rahul first combined three `3 Omega` resistors inparallel to obtain a resistance of `1 Omega`. He then connected six `3 Omega` resistors in parallel to obtain a resistance of `0.5 Omega`. These two parallel combinations were then connected in SERIES to obtain a resistance of `1 + 0.5 = 1.5 Omega` (see Figure 1) (b) Nine `3 Omega` resistors.  (c) In order to obtain `10 Omega` resistance, Rahul first connected three `3 Omega` resistors in parallel to obtain a resistance of `1 Omega`. He then connected three `3 Omega`resistors in series to get a resultant resistance of `9 Omega`. The parallel combination and series combination were then connected in series to obtain a final resistance of `1 + 9 = 10 Omega` (see Figure 2). (d) Six `3 Omega` resistors. (e) Rahul showed the values of (i) Knowledge of combination of resistors (II) Application of knowledge, and (iii) DESIRE ot help others. |
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