Rajeev throw three dice at the same time. Find the probability of gett

1.	Rajeev throw three dice at the same time. Find the probability of getting a total of at most 61. 6/542. 53/543. 5/544. 7/545. 8/91
Answer» Correct Answer - Option 3 : 5/54 Given: Rajeev = threw 3 dices at same time Formula used:- P(E) = Number of favorable outcomes/Total outcomes Calculation: Here, total number of possible outcomes = 6 × 6 × 6 ⇒ No. of event of getting sum of at most of 6 is (1, 1, 1), (1, 1, 2), (1, 2, 1), (2, 1, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1), (1, 2, 2), (2, 1, 2), (1, 1, 4), (1, 4, 1), (4, 1, 1), (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1) and (2, 2, 2) ⇒ probability of getting total of at most 6 = 20/216 ∴ probability of getting a total of at most 6 is 5/54

Rajeev throw three dice at the same time. Find the probability of getting a total of at most 61. 6/542. 53/543. 5/544. 7/545. 8/91

Answer» Correct Answer - Option 3 : 5/54

Given:

Rajeev = threw 3 dices at same time

Formula used:-

P(E) = Number of favorable outcomes/Total outcomes

Calculation:

Here, total number of possible outcomes = 6 × 6 × 6

⇒ No. of event of getting sum of at most of 6 is (1, 1, 1), (1, 1, 2), (1, 2, 1), (2, 1, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1), (1, 2, 2), (2, 1, 2), (1, 1, 4), (1, 4, 1), (4, 1, 1), (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1) and (2, 2, 2)

⇒ probability of getting total of at most 6 = 20/216

∴ probability of getting a total of at most 6 is 5/54

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