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Rama tested the solubility of four substances at different temperatures and found in grams of each substance dissolved in 100 g of water to form a saturated solution.{:(,"Substance dissolved",,"Temperature (K)",),(,"(in grams)","293 K","313 K","333 K"),(1.,"Ammonium chloride","37 g","41 g","55 g"),(2.,"Potassium chloride","35 g","40 g","46 g"),(3.,"Sodium chloride","36 g","36 g","37 g"),(4.,"Potassium nitrate","32 g","62 g","106 g"):}(i) Which substance is least soluble at 293 K. (ii) Which substance shows maximum change in its solubility when the temperture is raised from 293 K to 313 K ? (iii) Find the amount of ammonium chloride that will separate out when 55 g of its solution at 333 K is cooled to 293 K. (iv) What is the effect of temperature on the solubility of a salt ? (v) What mass of sodium chloride would be needed to make a saturated solution in 10 g of water at 293 K ? |
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Answer» Solution :(i) Potassium nitrate is least soluble in water at 293 K. (ii) Potassium nitrate shows maximum change in its solubility which is 30 g (62-32) per 100 g of water. (iii) From the available INFORMATION, 55 g of ammonium chloride solution UPON cooling from 333 K to 293 K SEPARATES salt = (55 - 37) = 18 g. (iv) From the available information, it is clear that the solubility of salt in water increases with the rise in temperature At 293 K, in a saturated solution, 100 g of water has SODIUM chloride = 36 g 10 g of water has sodium chloride = 3.6 g |
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