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Rate constant of a reaction with a virsus is `3.1 xx 10^(-4) s^(-1)`. Time required for a virus to become `75%` inactivated isA. `17.5 min`B. `40 min`C. `74.5 min`D. `40 min` |
Answer» Correct Answer - C Virsus inactivation follows first order kinetics based on unit of `k(s^(-1))`. `t_(50) = (0.693)/(k) = (0.693)/(3.1 xx 10^(-4)s^(-1)) = 2235s` `:. t_(75) = 2 xx t_(50) = 4470s = (4470)/(60) = 74.5 min` |
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