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Rate law for the reaction `A + B to ` product is rate `=K [A]^(2) [B].` What is the rate of reaction at a given temperature is `0.22Ms^(-1)` , when [A]=1 M and [B]=0.25 M?A. `3.52M^(-2)s^(-1)`B. `0.88M^(-2)s^(-1)`C. `1.136M^(-2)s^(-1)`D. `0.05M^(-2)s^(-1)` |
Answer» Correct Answer - B For reaction, `A+BrarrProduct` `dx/dt=k[A]^(2)[B]Rightarrow0.22=k(1)^(2)0.25` `therefore" "k=0.22/0.22=0.88" "M^(-2)s^(-1)` |
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