1.

Ratio of loss in solvent to gain in `CaCl_(2)` tube isA. `(p^(@))/(p)`B. `(p)/(p^(@))`C. `(p^(@) - p)/(p^(@))`D. `(p-p^(@))/(p)`

Answer» Correct Answer - C
`because` Loss in the weight of solvent = `p^(@) - p`
`because` Gain in the weight of `CaCl_(2) ` tube = `p^(@)`
`implies ("Loss in the weight of solvent")/("Gain in the weight of" CaCl_(2) "tube") = (p^(@) - p)/(p^(@))`


Discussion

No Comment Found

Related InterviewSolutions