1.

Reaction : FeCl_3+H_2StoFeCl_2+HCI=S in the above reaction

Answer»

`H_2S` is the REDUCING AGENT
`FeCl_3` UNDERGO oxdidation
`H_2S` ACTS as an reducing agent
`FeCl_3` acts as a reducing agent

SOLUTION :N/A


Discussion

No Comment Found