Read the scenario and solve these two problems.When traveling at top s

1.	Read the scenario and solve these two problems.When traveling at top speed, a roller coaster train with a mass of 12,000 kg has a velocity of 30 m/s. The kinetic energy of the train at top speed isJ.Given this kinetic energy, what is the tallest hill this roller coaster train can reach the top of?The train can climb a hill that ism high.Pls help im timed!!!!!!!!!!!!:c
Answer» Given: When traveling at top speed, a roller COASTER train with a mass of 12,000 kg has a velocity of 30 m/s. To FIND: KINETIC Energy of the train ? Max HEIGHT of the hill , it can climb ? Calculation: Kinetic Energy is a subtype of mechanical energy poses by the body by virtue of its motion. $\sf \therefore \: KE = \dfrac{1}{2} m {v}^{2}$ $\sf \implies \: KE = \dfrac{1}{2} \times 12000 \times {(30)}^{2}$ $\sf \implies \: KE = 6000 \times {(30)}^{2}$ $\sf \implies \: KE = 6000 \times 900$ $\boxed{ \sf \implies \: KE = 54 \times {10}^{5} \: joule}$ Now, while climbing the tallest hill, the whole kinetic energy will be converted to potential energy of the roller coaster. $\sf \implies \: KE = 54 \times {10}^{5} = PE$ $\sf \implies \: mgh = 54 \times {10}^{5}$ $\sf \implies \: 12000 \times 10 \times h = 54 \times {10}^{5}$ $\sf \implies \:1.2 \times {10}^{5} \times h = 54 \times {10}^{5}$ $\sf \implies \:h = \dfrac{54}{1.2}$ $\sf \implies \:h = 45 \: metres$ So, height of tallest hill is 45 metres.