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| 1. |
Reduce `(1/(1-4i)-2/(1+i))((3-4i)/(5+i))`to the standard form. |
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Answer» `z = (1/(1-4i)-2/(1+i))((3-4i)/(5+i))` `=((1+i-2+8i)/((1-4i)(1+i)))((3-4i)/(5+i))` `=((-1+9i)/(1+i-4i+4))((3-4i)/(5+i))` `=((-1+9i)/(5-3i))((3-4i)/(5+i))` `=((-1+9i)(3-4i))/((5-3i)(5+i))` `=(-3+4i+27i-36i^2)/(25+5i-15i-3i^2)` `=(-3+4i+27i+36)/(25+5i-15i+3)` `=(33+31i)/(28-10i)**(28+10i)/(28+10i)` `=(924+868i+330+310i^2)/(784-100i^2)` `=(924+868i+330i-310)/(784+100)` `=(614+1198i)/884` `z = 307/442+599/442i` |
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