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Resistance of a galvanometer is G Shunt used to allow 1 % of maincurrent through the galvanometer is

Answer»

Given:Ig=1%IGalvanometer resistance=GShunt resistance=?Formula:S=G.Ig/(I-Ig)Solution:S=G(1%I)/(1-1%I)=G(1%/99%)=G/99 ohmsS=G/99 ohms



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