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Resistance of a metal wire of length 5 m is 100 Ω. If the area ofcross-section of the wire is 3 × 10-7 m2, calculate the resistivity ofthe metal(b) |
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Answer» Formula : R = þ × length/Cross section area We have , Resistance, Length and Area has been given. ↪ Resistance = 100 Ω, ↪ Cross section area = 3 × 10⁻⁷ m² ↪ Length = 5 m ↪ 100 = þ × 5 ÷ ( 3 × 10⁻⁷ ) ↪ 100( 3 × 10⁻⁷ ) ÷ 5 = þ ↪ 20 × 3 × 10⁻⁷ = þ ↪ 6 × 10⁻⁷⁺¹ = þ ↪ 6 × 10⁻⁶ Ω = þ Therefore, Required Resistivity of resistance of metal is 6 × 10⁻⁶ Ω meters . |
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