1.

Resistance of a metal wire of length 5 m is 100 Ω. If the area ofcross-section of the wire is 3 × 10-7 m2, calculate the resistivity ofthe metal(b)

Answer»

Formula : R = þ × length/Cross section area

We have , Resistance, Length and Area has been given.

↪ Resistance = 100 Ω,

↪ Cross section area = 3 × 10⁻⁷ m²

↪ Length = 5 m

↪ 100 = þ × 5 ÷ ( 3 × 10⁻⁷ )

↪ 100( 3 × 10⁻⁷ ) ÷ 5 = þ

↪ 20 × 3 × 10⁻⁷ = þ

↪ 6 × 10⁻⁷⁺¹ = þ

↪ 6 × 10⁻⁶ Ω = þ

Therefore, Required Resistivity of resistance of metal is 6 × 10⁻⁶ Ω meters .



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