Ritu wears peneil heel shoes. Each heel has an area of contact as 0.00

1.	Ritu wears peneil heel shoes. Each heel has an area of contact as 0.001 m². If Ritu's weight is 350 N, what is the total amount of pressure when she stands on the floor ? [7 x 105 Pa
Answer» Explanation: Solution Mass of the girl, m=50kg Diameter of the heel, d=1cm=0.01m Radius of the heel, r= 2 d =0.005m Area of the heel =πr 2 =π×(0.005) 2 =7.85×10 −5 m 2 FORCE EXERTED by the heel on the floor: F=mg =50×9.8 =490N PRESSURE exerted by the heel on the floor: P= Area Force =490/(7.85×10 −5 )=6.24×10 6 N/m 2 Therefore, the pressure exerted by the heel on the horizontal floor is 6.24×10 6 N/m 2 .

Ritu wears peneil heel shoes. Each heel has an area of contact as 0.001 m². If Ritu's weight is 350 N, what is the total amount of pressure when she stands on the floor ? [7 x 105 Pa

Answer»

Explanation:

Solution

Mass of the girl, m=50kg

Diameter of the heel, d=1cm=0.01m

Radius of the heel, r=

=0.005m

Area of the heel =πr

=π×(0.005)

=7.85×10

−5

FORCE EXERTED by the heel on the floor:

F=mg

=50×9.8

=490N

PRESSURE exerted by the heel on the floor:

Area

Force

=490/(7.85×10

−5

)=6.24×10

N/m

Therefore, the pressure exerted by the heel on the horizontal floor is 6.24×10

N/m

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Ritu wears peneil heel shoes. Each heel has an area of contact as 0.001 m². If Ritu's weight is 350 N, what is the total amount of pressure when she stands on the floor ? [7 x 105 Pa​

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Ritu wears peneil heel shoes. Each heel has an area of contact as 0.001 m². If Ritu's weight is 350 N, what is the total amount of pressure when she stands on the floor ? [7 x 105 Pa