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`S_(("rhombic"))+O_(2(g))rarr SO_(2(g)) , Delta H =-297.5 K J` `S_(("monoclinic"))+O_(2(g))rarr SO_(2) , Delta H = - 300 K J` The data can predict that -A. Rhombic sulphur is yellow in colourB. Monoclinic sulphur has metallic lustureC. Monoclinic sulphur is more stableD. `Delta H` transition of `S_(R )` to `S_(M)` is endothermic |
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Answer» Correct Answer - D `S_(R )+O_(2)rarr SO_(2) , Delta H_(1)=-297.5 kJ` `S_(M)+O_(2)rarr SO_(2), Delta H_(2) = -300 kJ` `S_(R )rarr S_(M) , Delta H_(3) = ?` eq(iii) = eq(i) - eq(ii) `Delta H_(3)=-297.5-(-300)` `Delta H_(3)=+2.5 kJ` so, it endothermic process. |
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