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Scienists are working hard to develop inclear fusion reactor Nocies of heavy hydrogen, `_(1)^(2)H` , known as deuteron and denoted by `D`, can be thought of as a candidate for fusion rector . The `D-D` reaction is `_(1)^(2) H + _(1)^(2) H rarr _(2)^(1) He + n+ energy` in the core of fasion reactor a gas of heavy hydrogen of `_(1)^(2) H` nucles and electrons is know as plasma . The nuclei move randonity in the reactor to take place Unally , the temperature in the reactor core are too ligh and to natrual will can be used to confine the to pleama for a time l_(0) before the particles by away from the case if `n` is the denasity (number volume ) of determines , the product` nt_(0) `is called Lavson number in one of the criteria , a reactor is termed successful if Lawson number is greater then `5 xx 10^(14) s//cm^(2)` it may be helpfull to use the following botczmann constant `lambda = 8.6 xx 10^(-5)eV//k, (e^(2))/(4 pi s_(0)) = 1.44 xx 10^(-9) eVm` Result of calulations for fopur different desine of a fasion reactor using `D-D` reaction are given below which of these is most promising based on Lawson crierion ?A. deuteron density `= 2.0 xx 10^(12) cm^(-3)`, confinement time `= 5.0 xx 10^(-3)s`B. deuteron density `= 8.0 xx 10^(14) cm^(-3)`, confinement time `= 9.0 xx 10^(-1)s`C. deuteron density `= 4.0 xx 10^(23) cm^(-3)`, confinement time `= 1.0 xx 10^(-11)s`D. deuteron density `= 1.0 xx 10^(24) cm^(-3)` confinement time `= 4.0 xx 10^(-12)s` |
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Answer» Correct Answer - B for the reading `B` get `nt_(0) gt 5 xx 10^(14) ` which is the Lawson criterion for a reactor to work successfully |
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