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सदिश ` hati + 2hatj - hatk " तथा" 6hati - 3hatj + 2hatk` के बीच में के कोण की कोज्या ज्ञात कीजिए |

Answer» माना ` veca = 2hati + 2hatj - hatk "तथा" vec b = 6hati - 3hatj + 2hatk `
`vec a. vecb = (2hati + 2hatj -hatk) . (6hati - 3hatj + 2hatk )`
` = 2.6 + 2.(-3) + )-1).2 = 12 - 6 - 2 = 4 `
`|veca| = sqrt([(2)^(2) +(2)^(2) + (-1)^(2)]) = sqrt( 4 + 4 + 1) = sqrt(9) = 3`
`|vecb| = sqrt([(6)^(2) +(-3)^(2) + (2)^(2)]) = sqrt( 36 + 9 + 4) = sqrt(49) = 7`
`cos theta = (veca.vecb)/(|a|.|b|) = (4)/(3.7)= (4)/(21)`


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