InterviewSolution
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InterviewSolution
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`sec^(2)xtan y dx+sec^(2)ytan xdy=0` |
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Answer» `sec^(2)xtan y dx+sec^(2)ytan xdy=0` `implies (sec^(2)x)/(tan x)dx+(sec^(2)y)/(tany)dy=0` `implies int (sec^(2)x)/(tanx)dx+int(sec^(2)y)/(tan y)dy=c_(1)` `implies int(1)/(t)dt+int(1)/(z)dz=c_(1)` implies log t + log z = log c implies t.z = c implies tan x. tan y = c माना tan x = t `implies sec^(2)x dx = dt` और tan y = z `implies sec^(2)y dy = dz` (जहाँ `c_(1)=logc`) |
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