1.

See the sum of all three digits that are multiples of six See the sum of all three digits that are multiples of six​

Answer»

Answer:

a_{n}=a+(n-1)d  --- (1)

S_{n} =\frac{n}{2} [2a+(n-1)d]  --- (2)

Explanation:

The QUESTION is to find the sum of an AP.

First three digit DIVISIBLE by 6, hence a=102.

common difference=6, The last digit of AP is 996.

Hence SOLVING (1) , we get

n=150

Then solving (2) , we get

Sum= 82,350

Hope it helped...



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